Aprojectile of mass 6.8 kg kg is shot horizontally with an initial speed of 14.5 m/s from a height of 26.7 m above a flat desert surface. the acceleration of gravity is 9.81 m/s². for the instant before the projectile hits the surface, find the work done on the projectile by gravity. answer in units of j.

Explanation:

Given

mass of projectile

initial horizontal speed

height

Considering vertical motion

velocity gained by projectile during 26.7 m motion

v=final velocity

u=initial velocity

a=acceleration

s=displacement

Horizontal velocity will remain same as there is no acceleration

final velocity

Initial kinetic Energy

Final Kinetic Energy

Work done by all the force is equal to change in kinetic Energy of object

Work done by gravity is

hèllo, sorry i really need some more points so if you need this qustion answered than retype it

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)