Consider a string stretched between two supports. the speed of the propagation of transverse waves is 85 m/s, and two successive standing-wave frequencies are 510 hz and 680 hz. a) what is the order of these two harmonics (first, second, b) what is the length of the string?

To solve this problem we will use the definition of harmonics of a frequency for which we know that

Here

n = Number of Harmonic

V = Velocity

L = Length

Our values are given as

Now we have that the difference between two frequencies of different harmonics is

Now using this value in the expression of the fundamental frequency we have

Order of two harmonies is 3 and 4.

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.