Oscilloscope trigger problem. the 'trigger' settings determine when the trace begins. suppose you have displayed a sine wave with v = vosin(? t)vosin(? t) on the screen, where vo=5vvo=5v and ? /2? =5khz? /2? =5khz. assume further that the signal triggers the scope when v=2.5vv=2.5v and ? t=30 degrees? t=30 degrees. example: suppose you double the amplitude of the wave without changing any oscilloscope settings. what are vv and ? t? t now when the scope is triggered? [ the level hasn't changed so the scope still triggers when v=2.5vv=2.5v. v=2.5=10sin(? t)v=2.5=10sin(? t); ? t=sin? 1(2.5/10)=14.4775121851511 degrees? t=sin? 1(2.5/10)=14.4775121851511 degrees.]question: assume that you reduce vovo back to 5 v and switch the trigger slope polarity from '+' to '-' without changing the trigger level dial. what are v and ? ? t when the scope is triggered now?
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Physics, 22.06.2019 09:00
When a bicycle coasts uphill, it moves slower and slower as it climbs. why? a. its kinetic energy is transforming into heat energy. b. its potential energy is transforming into kinetic energy. c. its kinetic energy is transforming into potential energy and heat energy. d. its potential energy is transforming into kinetic energy and heat energy.
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Physics, 22.06.2019 09:30
In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the system if the initial energy was 2000 j? 1. write the equation 2.list out your known variables 3.plug the numbers into the equations 4.solve 5.write your solution statement that includes initial energy and final
Answers: 3
Oscilloscope trigger problem. the 'trigger' settings determine when the trace begins. suppose you ha...
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