Asmall dense ball with mass 1.5 kg is thrown with initial velocity < 3, 6, 0> m/s at time t - 0 from a location we choose to call the origin (< 0, 0, 0 > m). air resistance is negligible. when the ball reaches its maximum height, what is its velocity?

y = 1.84 m ,   v= ( 3, 0 ,0) m/s

Explanation:

This is a projectile launching exercise, at the point of maximum height the vertical speed is zero

                ² =  ² - 2 g y

                  = 0

                 y =  ² / 2g

The components of the initial velocity are

                  v₀ₓ = 3 m / s

                    = 6 m / s

Let's calculate

               y = 6 2/2 9.8

               y = 1.84 m

At this point the speed is only horizontal

               v = vox = 3 m / s

               v = 3i  m/s

               v= ( 3, 0 ,0) m/s

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

compass can be used day and night, cloudy or sunny