Objects a and b are both positively charged. both have a mass of 300 g , but a has twice the charge of b. when a and b are placed 60 cm apart, b experiences an electric force of 0.50 n .

a. how large is the force on a? n
b. what are the charges on qa and qb?
c. if the objects are released, what is the initial acceleration of a? (m/s^2)

(a). The force on A is same as that of charge B.

(b). The charge of and is and .

(c). The acceleration is 1.67 m/s².

Explanation:

Given that,

Mass of both objects = 300 g

A has twice the charge of B

Distance = 60 cm

Electric force = 0.50 N

Let the charge on B is q and on A is 2q.

(a). We need to calculate the force on A

The force on charge A is also same as that of charge B due to newton's third law of motion.

(b). We need to calculate the charges on and

Using formula of force

Put the value into the formula

The charge of is

Put the value of Q

The charge of is

(c). We need to calculate the acceleration

Using formula of acceleration

Hence, (a). The force on A is same as that of charge B.

(b). The charge of and is and .

(c). The acceleration is 1.67 m/s².