Awire contains a steady current of 2 a. the number of electrons that pass a cross section in2 s is: a. 2b. 4c. 6.3 × 10^18d. 1.3 × 10^19e. 2.5 × 10^19

Number of electrons,

Explanation:

Given that,

Current flowing in wire, I = 2 A

Time, t = 2 s

We need to find the number of electrons that passes through a cross section. The electric current is defined as the electric charge per unit time. It is given by :

Since, q = ne

n is the number of electrons

So, there are passes through a cross section. Hence, this is the required solution.

0.19 m/s and 0.45 m/s

0.11 m/s and 0.28 m/s should be correct