Arotating object starts from rest and has a constant angular acceleration. three secondslater the centripedal acceleration of a point on the object is 2m/s^2 . what is the magnitude of the centripedall acceleration of this point six seconds after the motion beings?

To solve this problem we will apply the kinematic equations of angular motion, we will begin by defining the centripetal acceleration which is given by,

Here,

v = Tangential velocity

r = Radius

The tangential velocity is also,

Where is the angular velocity, then the expression of centripetal acceleration is,

At the same time the angular velocity can be expressed in terms of angular acceleration as

At t = 3s

Then at t = 6s

Since r is constant, we have proportionally that the centripetal acceleration is proportional to the square of the angular velocity

Then the relation between two acceleration is

At 6s the centripetal acceleration would be

Therefore the magnitude of the centripedal acceleration of this point six seconds after the motion beings is

6/12=1/2

step-by-step explanation: