If a ball is thrown in the air with a velocity 48 ft/s. its height in feet t seconds later is given by y =48t-16t2. (round your answers to one decimal place.)

a. find the average velocity for the time period beginning when t = 2 and lasting 0.5 second.
b. find the average velocity for the time period beginning when t = 2 and lasting 0.05 second.
c. find the average velocity for the time period beginning when t = 2 and lasting 0.01 second.
d. estimate the instantaneous veiocity when t=2.

(a)-24 ft/s

(b)-16.8 ft/s

(c)-16.16 ft/s

(d) -16 ft/s

Explanation:

The initial velocity, v=48 ft/s

(a)

The average velocity when t=2 and 0.5 seconds later hence t=2.5 is given by

(b)

The average velocity when t lasts 0.05 second then

t=2 and t=2.05 is given by

(c)

The average velocity when t=2 and lasts 0.01 s then t=2.01 then is determined by

(d)

As the intervals get small, that is to imply from 0.05 s later to 0.01 s later as seen in parts a to c, the values are getting small and closer to 16 hence the instantaneous velocity at t=2 is -16 ft/s

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explanation: