Show that the intensity i is the product of the energy density u (energy per unit volume) and the speed of propagation v of a wave disturbance; that is, show that i = uv. (b) calculate the energy density in a sound wave 4.82 km from a 47.5 kw siren, assuming the waves to be spherical, the propagation isotropic with no atmospheric absorbtion, and the speed of sound to be 343 m/s.

a)I= E/A  = energy per unit volume * speed of propagation

b)energy density= 51.82 * 10 ^-9 j / m ^2

c) Intensity, is the amount of power crossing unit area perpendicular to the direction of the flow.intensity is related as

                                            I =U * V

d) energy density = 3.59*10 ^-5 space per unit volume.

Explanation:

a)

I = E/A

multiplying num and den by u

I = (Ev) / (Av)= (E / (u)) * u

= energy per unit volume * speed of propagation

b)

energy density

= 50kw / surface area

= 51.82 * 10 ^-9 j / m ^2

a)

In describing any flow of energy through space,it is useful to talk in terms of the power crossing unit area perpendicular to the flow,this is the intensity, usually denoted by I

intensity, is the amount of power crossing unit area perpendicular to the direction of the flow.intensity is related as

                                            I =U * V

b)

energy density of a radio wave=50000 / 4p (480) ^3

=3.59*10 ^-5 space per unit volume.

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

happy to

pls mark as brainliest.

the assestment will probley apele with cause and effect