An airplane is flying in a horizontal circle at a speed of 92.1 m/s. the 55.6 kg pilot does not want his radial acceleration to exceed 8.45 g. the acceleration of gravity is 9.8 m/s². what is the minimum radius of the circular path?

 r = 102.43 m

Explanation:

Newton's second law for this case is

              F = ma

Where the acceleration is centripetal

            a = v² / r

            r = v² / a

They indicate that the radial acceleration is 8.45 g

           r = v² / 8.45 g.

           r = 92.1² / 8.45 9.8

           r = 102.43 m

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

it is called kinetic energy