Aparachutist with a camera, both descending at a speed of 10.8 m/s, releases that camera at an altitude of 50 m. in this problem, take "up" to be positive.

The velocity of the camera is 33.11 m/s.

Explanation:

Given that,

Speed = 10.8 m/s

Altitude = 50 m

Suppose determine the velocity of the camera just before it hits the ground?

We need to calculate the velocity of the camera

Using equation of motion

Where, v = final velocity of camera

u = initial speed of camera

s = distance

Put the value into the formula

The direction will be downward so it is the negative velocity.

Hence, The velocity of the camera is 33.11 m/s.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2