Amachine part is undergoing shm with a frequency of 5.00hz and amplitude 1.80cm . how long does it take the part to gofrom x=0 to x= -1.80 cm?

To solve this exercise we will use the expression of the displacement in the aromatic movement in the two given points. Thus we will find the value of time as a function of frequency. In the end we will replace that value and find the time taken,

The expression for the displacement of the object in simple harmonic motion is

At the initial position the value of x is zero,

Now the expression for the displacement of the object in simple harmonic motion is

At the final position the value of x is -1.8cm

Replacing we have that

The total change in time will be

Replacing the value of the frequency we have that

Therefore the time taken for the displacement in the interval of x=0 to x=-1.8 is 0.05s

the answer is b i think