Two protons are moving directly toward one another. when they are very far apart, their initial speeds are 1.50 x 105 m/s. what is the distance of closest approach?

To solve this problem we will start from the conservation of energy. Here we will have that the kinetic energy must be equivalent to the potential energy. That is

Here,

m = mass

v = Velocity

Coulomb constant

 Charge Proton

r = Distance

Equation both expression we have that

The kinetic energy is multiplied by two, by the existence of the two protons.

Replacing the values we have that

Therefore the distance of closest approach is

d) physical means can be used to separate the components of air.

answer; how far out of place which the object finished relative to the starting location;