An lp turntable must spin at 3.500 rad/s to play a record. how much torque must the motor deliver if the turntable is to reach its final angular speed in 1.800 revolutions, starting from rest? the turntable is a uniform disk of diameter 30.80 cm and mass 0.2500 kg.

0.00321 Nm

Explanation:

= Final angular velocity = 3.5 rad/s

= Initial angular velocity = 0

= Angular acceleration

= Angle of rotation = 2 rev

Equation of rotational motion

Moment of inertia is given by

Torque is given by

The torque required is 0.00321 Nm

your answer is c! hope this : )

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