If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level location? assume an air temperature of 20∘c.

QUESTION: The question is incomplete. See the complete question below and the answer.

The classic Goodyear blimp is essentially a helium balloon— a big one, containing 5700 m3 of helium. If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level location? Assume an air temperature of 20°C.

Mass of the cargo load  = 1548.2kg

Explanation:

Calculating the weight of helium gas, we have

W = mg

   = (pv)g

   =(0.178 * 5700)g

   =(1014.6)g

Weight of envelope and gondola;

W = (4300kg)g

Weight of cargo load = mg (unknown)

The upthrust force on the balloon is calculated as;

F =pvg

  = (1.204 *5700)g

  =(6862.8)g

But;

Weight of helium gas + weight of envelope and gondola + weight of cargo = upthrust force on the balloon.

Substituting, we have;

(1.0146)g +  (4300kg)g + mg = (6862.8)g

mg =  (6862.8)g - (1014.6)g - (4300kg)g

 mg    = (1548.2kg)g

m =  (1548.2kg)g/g

m = 1548.2kg

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.