Two 3.3 g bullets are fired with speeds of 38.0 m/s and 83.7 m/s, respectively. a) what is the kinetic energy of the first bullet

Explanation:

Kinetic energy is given by

         Kinetic energy = 0.5 x Mass x Velocity²

Here mass and velocity is given we need to find kinetic energy.

         Mass, m = 3.3 g = 3.3 x 10⁻³ kg

         Velocity, v = 38.0 m/s

Substituting

         Kinetic energy = 0.5 x Mass x Velocity²  

         Kinetic energy = 0.5 x 3.3 x 10⁻³ x 38.0²  

         Kinetic energy = 2.38 J

Kinetic energy of the first bullet is 2.38 Joules        

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explanation: