If the beam carries 1015 electrons per second and is accelerated by a 350 kv source, find the current and power in the beam.

To solve this problem we will apply the concept of current defined as the electron charge flow by the number of electrons per second. That is,

I = q*N

Here q is Flow of electric charge in one second and N the number of electron flow per second.

A the same time the power is described as the applied voltage for the current.

P = VI

We know the charge of electron, Coulombs, then the current is

And the power in the Beam is

an electric circuit

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