Abattery with an emf of 12 v connects in parallel to a 50 ω and 25 ω resistor. the current through the battery is 0.70 a. what is the internal resistance of the battery?

r = 0.47 Ω

Explanation:

given,

voltage of the battery = 12 V

resistors are connected in parallel.

R₁ =  50 Ω         and   R₂ = 25 Ω

current,I = 0.70 A

Internal resistance = ?

equivalent resistance

now,

 r is the internal resistance

     16.67 + r = 17.14

       r = 0.47 Ω

Hence, internal resistance of the battery is equal to r = 0.47 Ω

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right