At room temperature, an oxygen molecule, with mass of 5.31x10^-26kg , typically has a kinetic energy of about 6.21x10^-21j. how fast is it moving?

V=483.63 m/s

Explanation:

Given that

mass ,m= 5.31 x 10⁻²⁶ kg

Kinetic energy KE= 6.21 x 10⁻²¹ J

As we know that the kinetic energy of the mass m with moving velocity V given as

Now by putting the values

V=483.63 m/s

Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.

if they have a finite resultant

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