You place a +1.00 mc charged object in an electric field of 900 n/c that points due east. determine the magnitude and direction of the force on the object.

0.9 N, east

Explanation:

charge, q = 1 mC = 0.001 C

Electric filed, E = 900 N/C due east

Force, F = q E

F = 0.001 x 900

F = 0.9 N

The direction of force is same as the direction of electric field as the charge is positive in nature. So, the direction of force is also east.

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