Suppose you have to move a heavy crate of weight 875 {\rm n} by sliding it along a horizontal concrete floor. you push the crate to the right with a horizontal force of magnitude 300 {\rm n}, but friction prevents the crate from sliding. now assume that the crate is sliding along the floor with constant velocity. what is the magnitude f_p of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?

To solve this problem it is necessary to apply the concepts related to the Friction Force, which is given from the multiplication between the Normal Force (in a horizontal plane it is equivalent to the mass by gravity) and the kinetic coefficient of friction.

Since the statement the value of the coefficient of friction is not given, so I will assign a value of 0.5 between the crate and the ground. If another value has been provided for this coefficient, it will simply be necessary to replace it in the equation given below.

Where,

= Coefficient of friction

N = Normal Force

Replacing,

Therefore the friction force acting on the crate is 437.5N

im guessing the west of station b

98.4 m

explanation:

let s = distance up the plane  

then by conservation of energy  

1/2m(18.3)^2 = mg s sin(10)  

(18.3)^2 = 2g s sin(10)  

s = (18.3)^2/2gsin(10)  

= 98.39564526  

= 98.4 m