Acyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. if the car has a constant acceleration of 2.0 m/s2, when will the car overtake the cyclist?

After 6 seconds, the car will surpass the cyclist.

The speed of the cyclist = 6 m/s.

Let after time t sec, the car will overtake the cyclist.

So, distance covered by the cyclist in t sec = 6t m

Initial velocity of the car is 0 m/s, because the car is just starting.

Acceleration of the car =.

Final velocity of the car =6 m/s.

So to cover the distance 6t, the time required by the car =

t =6 sec

So, after 6 seconds, the car will surpass the cycle.  

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation:

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2