The length of a retanle is twice the width plus 10. if the perimenter of the rectangle must be 200 inches what is the maimumarea of the rectange?

Explanation:

The length of a rectangle is twice the width plus 10

Let L be the length and W be the width.

               L = 2W + 10

The perimeter of the rectangle must be 200 inches

           Perimeter = 2 (L+W) = 200

                              2(2W+10+W) = 200

                                 3W + 10 = 100

                                 3W = 90

                                    W = 30 inches

                 L = 2 x 30 + 10 = 70 inches

Area = Length x Width

Area = 30 x 70

Area = 2100 inch²

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