A3600 kg rocket traveling at 2900 m/s is moving freely through space on a journey to the moon. the ground controllers find that the rocket has drifted off course and that it must change direction by 11◦ if it is to hit the moon. by radio control the rocket’s engines are fired instantaneously (i. e., as a single pellet) in a direction perpendicular to that of the rocket’s motion. the gases are expelled (i. e., the pellet) at a speed of 4300 m/s (relative to the rocket). what mass of gas must be expelled to make the needed course correction? answer in units of kg.

m=417.24 kg

Explanation:  

Given Data

Initial mass of rocket  M = 3600 Kg

Initial velocity of rocket vi = 2900 m/s  

velocity of gas vg = 4300  m/s

Θ = 11° angle in degrees

To find

m = mass of gas  

Solution

Let m = mass of gas    

first to find Initial speed with angle given

So

Vi=vi×tanΘtan angle

Vi= 2900m/s × tan (11°)

Vi=563.7 m/s

Now to find mass

m = (M ×vi ×tanΘ)/( vg + vi tanΘ)

put the values as we have already solve vi ×tanΘ

m = (3600 kg ×563.7m/s)/(4300 m/s + 563.7 m/s)

m=417.24 kg

the components of a vector are the parts of the vectors that are to each other.

b perpendicular