Achemist must 35.5 dilute of 34.7 aqueous silver(ii) oxide solution until the concentration falls to . he'll do this by adding distilled water to the solution until it reaches a certain final volume. calculate this final volume, in milliliters. round your answer to significant digits.

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Q) A chemist must dilute 22.5mL of 119μ M aqueous silver(II) oxide AgO solution until the concentration falls to 65.0μ M . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to significant digits.

Final Volume V2 = 41.2 mL

Explanation:

We will start by first recalling the formula of dilution which goes by,

M1 * V1 = M2 * V2 (1)

Now let us consider V1 = 22.5 mL

M1 = 119μ M

M2 =  65.0μ M

lets substitute the values above in equation 1,

M1 * V1 = M2 * V2

V2 = (M1 * V1)/M2 ( I have created V2 as the subject here)

V2 = (119*22.5)/65

V2 = 41.2 mL

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the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia