Asimple harmonic oscillator has amplitude 0.76 m and
period2.9 sec. what is the maximum acceleration?

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Explanation:

To solve this problem we are going to consider the particle to be moving along the x axis and we are also going use the differential equation of the simple harmonic oscillator:

,

,

where is the displacement along the x axis from the equilibrium point, and is the angular frecuency.

We know that is the acceleration of the particle and that the angular frecuancy depends on the period:

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By substitution we get

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We get the maximum and minimum acceleration at a displacement equals the . Since we are moving along the x-axis, we get the maximum acceleration at .

So

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