2. an archer shoots an arrow at 83.0 m/s at a 62.0 degree angle. if the ground is flat, how much time is the arrow in the air?

t=14.96 sec

Explanation:

Diagonal Launch

It's a physical event that happens where an object is thrown in free air (no friction) forming an angle with the horizontal reference. The object then describes a path called a parabola.

The object will reach its maximum height and then return to the height from which it was launched. The equation for the height is :

Where vo is the initial speed, is the angle, t is the time and g is the acceleration of gravity .

In this problem we'll assume the arrow was launched from the ground level (won't consider the archer's height). Thus , and:

The value of y is zero twice: when t=0 (at launching time) and in t= when it goes back to the ground. We need to find that time by making

Dividing by

Then we find the total flight time as

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explanation: