Aforward-biased silicon diode is connected to a 12.0-v battery through a resistor. if the current is 12 ma and the diode potential difference is 0.70 v, what is the resistance?

To solve this problem we will use the concepts related to Ohm's law for which voltage, intensity and resistance are related.

Mathematically this relationship is given as

Where,

V= Voltage

I = Current

R = Resistance

The value of the given voltage is 12V, while the current is 12mA, therefore the resistance would be

Therefore the resistance is

newton's first law of motion

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