Kenny and candy decided to sit on a see-saw while visiting a local play park. candy, of mass
50 kg, sat 250 cm from the pivot of the seesaw.
(1). where should kenny, of 60 kg mass, sit so that a state of stable equilibrium exists?

(ii)
what should kenny do if he wanted to elevate candy?

(acceleration due to gravity = 10 n kg)

(i) 208 cm from the pivot

(ii) Move further from the pivot

Explanation:

(i) Sum of the moments about the pivot of the seesaw is zero.

∑τ = Iα

(50 kg) (10 N/kg) (2.5 m) + (60 kg) (10 N/kg) x = 0

1250 Nm + 600 N x = 0

x = -2.08 m

Kenny should sit 208 cm on the other side of the pivot.

(ii) To increase the torque, Kenny should move away from the pivot.

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

the answer is kevlar