Alate traveler rushes to catch a plane, pulling a suitcase with a force-directed 30.0 degrees above the horizontal. if the horizontal component of the force on the suitcase is 60.6 n, what is the force exerted on the handle?

F=  69.97 N

Explanation:

Given that

θ = 30°

Horizontal component of the force (F) = 60.6 N

Lets take force exerted on the  suitcase= F

The horizontal component = F cosθ

Given that

F cosθ= 60.6 N

F cos 30°= 60.6 N

We know that cos 30° = 0.866

F x 0.866 = 60.6 N

F=  69.97 N

Therefore the force on the suitcase will be 69.97 N

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