If an object with a density 0.25 g/ml has a mass of 10 grams, and is added to a graduated cylinder filled with 50 ml of water, how high will the water in the graduated cylinder rise?

a) 50.25 ml b) 52.5 ml c) 60 ml d) 90 ml e) 150 ml

Answer : The correct option is, (d) 90 mL

Explanation :

First we have to calculate the volume of an object.

As we know that,

Given:

Density of an object = 0.25 g/mL

Mass of an object = 10 g

Now put all the given values in the above formula, we get:

Thus, the volume of an object is 40 mL.

Now we have to calculate the height of the water in the graduated cylinder rise.

As we are given that:

The volume of water in graduated cylinder = 50 mL

The volume of an object = 40 mL

The height of the water in the graduated cylinder rise = Volume of water in graduated cylinder + Volume of an object

The height of the water in the graduated cylinder rise = 50 mL + 40 mL

The height of the water in the graduated cylinder rise = 90 mL

Therefore, the height of the water in the graduated cylinder rise will be, 90 mL

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards