Asolid wood door, 90.0 cm wide by 2.00 m tall has a mass of 35.0 kg. it is open and at rest. a small 500-g ball is thrown perpendicular to the door with a speed of 20.0 m/s and hits the door 60.0 cm from the hinged side. the ball rebounds with a speed of 16.0 m/s along the same line. what is the angular speed of the door just after the collision with the ball ?

w = 1.14 rad/s

Explanation:

Moment of inertia ()

Moment of inertia = 35 * 0.9^2 / 3 = 9.45 kg m^2

Impulse ("An impulse is equal to the net force on the object times the time period over which this force is applied. ")

Impulse = 0.5 * [16 - (- 20)]

Impulse = 18 kg m/s

angular momentum = M of I *angular speed  w

= 9.45 w

= impulse * distance  

= 18 * 0.6

 9.45 w = 18 * 0.6

w = 1.14 rad/s  

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this