Each plate of a parallel‑plate capacitor is a square of side 3.63 cm, and the plates are separated by 0.473 mm. the capacitor is charged and stores 8.49 nj of energy. find the electric field strength inside the capacitor.

E= 55.53 x 10³ V/m

Explanation:

Given that

a=  3.63 cm

Area ,A= a²

distance ,d= 0.473 mm

Stored energy ,U = 8.49 nJ

Value of capacitor given as

By putting the values

C=2.46 x 10⁻¹¹ F

V=Voltage difference

V=26.27 V

V= E d

E=Electric filed

26.27 = E x 0.473 x 10⁻³

E= 55.53 x 10³ V/m

d) physical means can be used to separate the components of air.