A36.5 kg box initially at rest is pushed 4.30 m along a rough, horizontal floor with a constant applied horizontal force of 150 n. if the coefficient of friction between box and floor is 0.300, find the following.
(a) the work done by the applied force
(b) the energy loss due to friction,
(c) the work done by the normal force,
(d) the work done by gravity,
(e) the change in kinetic energy of the box, and
(f) the final speed of the box

(a) The work done by the applied force is

(b) The energy loss due to friction is

(c) The work done by the normal force is

(d) The work done by gravity is

(e) The change in kinetic energy of the box is

(f) The final speed of the box is

Explanation:

Given:

Weight of the box

Distance

Horizontal force

Coefficient of friction between box and floor

Step 1:

(a) The work done is,

Substitute the values,

Therefore, the work done by the applied force is 645 J.

Step 2:

(b) The increase in internal energy in the box-floor system due to friction is given by,

Therefore, the energy loss due to friction is

Step 3:

(c) The work done by the normal force is Because, no displacement is taking place in that direction.

(d) The work done by gravity is also , as there is zero displacement in that direction.

Step 4:

The change in kinetic energy of the box is given by,

Δ

Δ

Therefore, the change in kinetic energy of the box is

Step 5:

(f) The final speed of the box is given by,

Therefore, the final speed of the box is

To learn more:

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.