The displacement x(t) of a particle from the origin at time t, t≥0, is x(t)=t^3+3t(t-3)+10. find min velocity?

0 m/s

Explanation:

given,

x(t)=t^3+3 t (t-3)+10

velocity

.............(1)

now, differentiating both side for minimum velocity calculation

now, equating derivative equal to zero

t = -1

again differentiating

hence, at t = -1 velocity will be minimum

now, inserting value of t in equation 1

 v = 0 m/s

hence, minimum velocity is equal to 0 m/s

ill do it for 100, also this isnt 80 its 40

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2