Asatellite is in circular orbit at an altitude of 1500 km above the surface of a nonrotating planet with an orbital speed of 9.2 km/s. the minimum speed needed to escape from the surface of the planet is 14.9 km/s, and g = 6.67 × 10-11 n · m2/kg2. the orbital period of the satellite is closest to

To solve this problem we will use the Newtonian theory about the speed of a body in space for which the speed of a body in the orbit of a planet is summarized as:

Where,

G = Gravitational Universal Constant

M = Mass of Planet

r = Radius of the planet ('h' would be the orbit from the surface)

The escape velocity is

Through this equation we can find the mass of the Planet in function of the distance, therefore

The orbital velocity is

The time period of revolution is,

Therefore the orbital period of the satellite is closes to 1 hour and 12 min

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

answer and explanation;