A200 kg wood crate sits in the back of a truck. the coefficients of friction between the crate and the truck are = 0.9 and = 0.5. the truck starts off up a 20° slope. what is the maximum acceleration the truck can have without the crate slipping out the back?

Maximum acceleration of the truck is 5.25 m/s^2

Explanation:

To find the maximum acceleration the truck first we need to calculate friction between truck and wood. Because of wood is not moving, coefficient of c_{s} need to be used for it. Then the formula will be:

1657.62 Newton is the friction.

So force against friction need to be at most 1657.62 N. Then equation will be:

Maximum acceleration of the truck need to be 5.25 m/s^2

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

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