An object of mass 0.50 kg is transported to the surface of planet x where the object’s weight is measured to be 20 n. the radius of the planet is 4.0 x 10^6 m. what free fall acceleration will the 0.50-kg object experience when transported to a distance of 2.0 x 10^6 m from the surface of this planet?

Explanation:

Given:

Now free fall acceleration on planet X:

irrespective of the height.

17.78 m/s^2

Explanation:

m = 0.5 kg

Weight on the planet, W = 20 N

Acceleration due to gravity on the surface of planet, g = W / m

g = 20 / 0.5 = 40 m/s^2

Radius of planet, r = 4 x 10^6 m

height, h = 2 x 10^6 m

Let the acceleration due to gravity at a height is g'.

According to the formula of acceleration due to gravity at height is

g' = 17.78 m/s^2

Thus, the acceleration due to gravity at height is  17.78 m/s^2 .

this could be newton#'s law of cooling. the cooling curve is exponential

the right answer is 0.3 meters per second