When 6.0 l of he(g) and 10. l of n2(g), both at 0oc and 1.0 atm, are pumped into an evacuated 4.0 l rigid container, the final pressure in the container at 0oc is

P2=4atm

Explanation:

When 6.0 L of He(g) and 10. L of N2(g), both at 0oC and 1.0 atm, are pumped into an evacuated 4.0 L rigid container, the final pressure in the container at 0oC is

from boyle's law which states that the pressure on a gieben mass of gas is inversely proportional to the volume provided that temperature is kept constant

P∝1/v

PV=k

where k is the constant of proportionality

the v1=6L+10L=16L

P1=1atm

P2=?

V2=4L

16*1=4*P2

P2=4atm

P1=pressure 1atm

V1=volume of helium with nitrogen gas

P2=final pressure

V2=4l volume space

this would be about 43%