The turnover number for an enzyme is known to be 500 min-1 . a mutant of the enzyme was made that resulted in the destabilization of the es complex of 1 kcal/mole, and a destabilization of transition state (es‡ ) of 2.5 kcal/mol. calculate the kcat of the mutant enzyme (assuming a temperature of 27°c). kcat = (kbt/h).e-(δg‡/rt) t = temperature in kelvin kb = 3.297 ×10−24 cal/k h = 1.583 x 10-34 cal. s r = 2 cal/k. mol

Explanation:

turnover number for an enzyme = 500/min

destabilization of the ES complex = 1Kcal/mole

destabilization of transition state (ES‡ ) = 2.5 kcal/mol

kB = 3.297×10−24 cal/K

h = 1.583 x 10-34 cal.s  

R = 2 cal/K.mol

we Know that

kcat = (kBT/h).e-(ΔG‡/RT)

T = temperature in Kelvin

By considering the following reaction

                                         K1                K2        

                             E  +  S  ⇆   (ES‡ )     ⇒         E + P

                                         K-1  

                               Ф  = K2(ES‡ )

where

               ΔG‡ = -RTlnKeq‡

     K‡eq

     K(cat)= Kb T/h   x    K2x ES‡/ES Now by putting values we get

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jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.