A0.110-kg cube of ice (frozen water) is floating in glycerine. the glycerine is in a tall cylinder that has an inside radius of 3.70 cm. the level of the glycerine is well below the top of the cylinder.
if the ice completely melts, by what distance does the height of the liquid in the cylinder change?

Answer

 Δ h = 0.06 m

Explanation:

Given,

mass of ice cube = 0.11 Kg

inside radius of cylinder = 3.70 cm

density of water = 1000 Kg/m³

density of glycerin = 1260 Kg/m³

ice cube is floating on glycerin surface,

net force on the cube is equal to zero.

Buoyant force by glycerin is equal to the weight of cube

     B = W

          h₁ = 0.0203 m

when ice melts it is completely turned into water

  Volume of mass m of water

         h₂ = 0.0803 m

distance by which height of liquid change

 Δ h = h₂ - h₁

 Δ h = 0.0803 - 0.0203

 Δ h = 0.06 m

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.