Arace car starts from rest on a circular track of radius 478 m. the car’s speed increases at the constant rate of 0.747 m/s 2 . at the point where the magnitudes of the centripetal and tangential accelerations are equal, find the speed of the race car

18.896ms-1

Explanation:

The tangential acceleration of the car= 0.747ms-2

The centripetal acceleration is given by v^2/r

0.747= v^2/r

V= √0.747*478= 18.896ms-1

lower, it's not as dense as chocolate syrup.

choco syrup is more like a solid than a liquid and even turns solid if it gets slightly cold,

orange juice however is a 95% liquid and has a very low viscosity

there was no answer choices but i think its representative