Acylinder is closed by a piston connected to a spring of constant 1.60 103 n/m. with the spring relaxed, the cylinder is filled with 5.00 l of gas at a pressure of 1.00 atm and a temperature of 20.0

The height is 0.247 m.

Explanation:

Given that,

Spring constant = 1.60\times10^3\ N/m[/tex]

Pressure = 1.00 atm

Temperature = 20.0°C

Suppose if the piston has a cross section area of 0.0120 m² and negligible mass, how high will it rise when the temperature is raised to 250°C

The equation of the pressure is

...(I)

The equation of the volume is

....(II)

We need to calculate the height

Using equation of ideal gas

Put the value of P' and V' from equation (I) and (II)

Put the value into the formula

Hence, The height is 0.247 m.

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

the answer would be   dignified - apex