A2.00-kg rock has a horizontal velocity of magnitude 12.0 m/s when it is at point p in fig. e10.35. (a) at this instant, what are the magnitude and direction of its angular momentum relative to point?

The magnitude and direction of its angular momentum relative to point is 115.28 kg m²/s.

Explanation:

Given that,

Mass = 2.00 kg

Velocity = 12.0 m/s

Suppose the distance from point O to point p and angle is 8.00 m and 36.9°.

We need to calculate the magnitude and direction of its angular momentum relative to point

Using formula of angular momentum

Where, r = distance from point O to point P

v = speed

= direction

Put the value into the formula

The direction of angular momentum is pointing into the page.

Hence, The magnitude and direction of its angular momentum relative to point is 115.28 kg m²/s.

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day