The volume of a sphere is increasing at a rate of 25\pi25π25, pi cubic meters per hour. at a certain instant, the volume is \dfrac{32\pi}{3} 3 32π start fraction, 32, pi, divided by, 3, end fraction cubic meters.

Explanation:

given,

rate of increase of volume of sphere = 25π m³/h

volume at certain time =

calculate the rate of change of surface area = ?

volume of sphere

    r³ = 8

    r = 2 m

surface are of the sphere

 A = 4 π r²

now,

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b.

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