An electromagnetic wave with frequency 65.0 hz travels in aninsulating magnetic material that has dielectric constant 3.64 andrelative permeability 5.18 at this frequency. the electric fieldhas amplitude 7.20 \times 10^{ - 3} {\rm v}/{\rm m}.a. what is the speed of propagation of the wave? b. what is the wavelength of the wave? c. what is the amplitude of the magnetic field? d. what is the intensity of the wave?

To solve this problem, it is necessary to apply the concepts related to the wavelength, frequency, speed and intensity of an electromagnetic wave.

The expression for the speed of the electromagnetic wave is described as

Where,

= Magnetic permeability

= Permeability of free space

= Permittivity of free space

The expression for the wavelength is

Where,

v = Velocity of wave

f = Frequency

The expression for the amplitude of the magnetic field is

Where,

v = Speed

= Amplitude of the maximum electric field

The expression for the intensity of the wave is as follows:

PART A ) Our values are given as

Replacing at our first equation we have,

Therefore the magnitude of the speed of the electromagnetic wave is equal to

PART B) The value of our frequency is 65Hz and the velocity was previously found, then

PART C) For the amplitude of the maximum magnetic field we have that

Replacing we have that

Therefore the amplitude of the maximum magnetic field is equal to

PART D) Finally the intensity is given as

Therefore the intensity of the wave is equal

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

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