A5 kg block moves with a constant speed of 10 ms to the right on a smooth surface where frictional forces are considered to be negligible.

it passes through a 2.0 m rough section of the surface where friction is not negligible, and the coefficient of kinetic friction between the block and the rough section μk is 0.2.

what is the change in the kinetic energy of the block as it passes through the rough section?

The change in the kinetic energy of the block as it passes through the rough section is 19.6 J.

Given data:

The mass of block is, m = 5 kg.

The speed of block is, v = 10 m/s.

Length of rough section is, d = 2 m.

The coefficient of kinetic friction between the block and the rough section is, .

As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.

So,

Thus, we can conclude that the change in the kinetic energy of the block as it passes through the rough section is 19.6 J.

Learn more about the work-energy concept here:

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Work done, W = 19.6 J

Explanation:

It is given that,

Mass of the block, m = 5 kg

Speed of the block, v = 10 m/s

The coefficient of kinetic friction between the block and the rough section is 0.2

Distance covered by the block, d = 2 m

As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.

W = 19.6 J

So, the change in the kinetic energy of the block as it passes through the rough section is 19.6 J. Hence, this is the required solution.

answer: its c lololo

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.