Amagnetic b field of strength 18 t is perpendicular to a conducting loop of wire measuring 0.9 square meters with 30 turns. if the b field is linearly reduced to zero in 4 s, then what is the magnitude of the induced emf voltage? (in units of v).

magnitude of the induced emf voltage = 121.5 V

Explanation:

given data

magnetic field of strength B =  18 T

area = 0.9 m²

no of turn = 30 turns

Δt = 4s

to find out

magnitude of the induced emf voltage

solution

we get her magnitude of the induced emf voltage that is express as

magnitude of the induced emf voltage =   ......1

magnitude of the induced emf voltage =

magnitude of the induced emf voltage =

magnitude of the induced emf voltage = 121.5 V

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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