Amotorcycle has a velocity of 24 m/s, due south as it passes a car with a velocity of 15 m/s due north. what is the magnitude and direction of the velocity of the motorcycle as seen by the driver or car?
a. 39 m/s, southb. 9 m/s, northc. 39 m/s, northd. 15 m/s, south

39 m/s north

Explanation:

Let us consider North direction as positive and south as negative

Velocity of motorcycle = -24 m/s

Velocity of car = +15 m/s

The Velocity of the motorcycle as seen by the driver or car

The speed of the motorcycle as seen by the driver or car is 39 m/s as it is positive the direction is north

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer