Asatellite is placed in a circular orbit with a radius equal to one-third the radius of the moon's orbit. what is its period of revolution in lunar months? (a lunar month is the period of revolution of the moon.)

0.19245 lunar months

Explanation:

T = Orbital time

r = Radius

1 denotes the moon

2 denotes the satellite

From Kepler's law we have

So,

The period of revolution of the satellite is 0.19245 lunar months

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s